“…To prove Theorem 1, then, it suffices to show that 100% of the fibres X P admit a set S of primes at which the relevant subgroup of Br X P / Br k is prolific. It was shown in [2] that, at least for v sufficiently large, the evaluation map at v corresponding to an element A of Br 1 X P only depends on the residue of A at v. To control these residues, we use the philosophy of [3]. Specifically, we generalise the following proposition.…”