“…Compound 2 was obtained as a yellow solid and its molecular formula was determined as C 25 H 28 O 5 by the HR‐ESI‐MS analysis ( m / z 409.2008, [ M + H] + ). The 1 H‐ and 13 C‐NMR spectra of 2 ( Tables and ) exhibited characteristics of the 3′‐substituted chalcone, as found for 1 . In its 1 H‐ and 13 C‐NMR spectra, an oxygenated CH group was observed at δ (H) 3.43 ( dd , J = 8.2, 3.8, H–C(4′′))/ δ (C) 77.7 (C(4′′)), three CH 2 groups at δ (H) 3.13 ( dd , J = 13.4, 11.3, H α –C(1′′)) and 2.80 ( dd , J = 13.4, 3.7, H β –C(1′′))/ δ (C) 22.1 (C(1′′)), 2.52 ( ddd , J = 12.8, 7.2, 5.4, H ax –C(6′′)) and 1.93 ( m , H eq –C(6′′))/32.7 (C(6′′)), and 1.76 – 1.84 ( m , H a –C(5′′)) and 1.52 – 1.63 ( m , H b –C(5′′))/32.9 (C(5′′)), a CH group at δ (H) 2.57 ( dd , J = 11.3, 3.7, H–C(2′′))/ δ (C) 51.4 (C(2′′)), and two Me groups at δ (H) 1.06 ( s , 3 H)/ δ (C) 27.1 (C(10′′)) and 0.96 ( s , 3 H)/18.2 (C(9′′)).…”