1965
DOI: 10.1063/1.1695743
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Cole—Cole Diagram and the Distribution of Relaxation Times

Abstract: The completeness of the Cole—Cole diagram in the analysis of dielectric relaxation is proved by showing explicitly that a semicircle in the Cole—Cole diagram corresponds uniquely to a Debye relaxation function. A method is established to distinguish a continuous distribution of relaxation times from a single relaxation time.

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Cited by 103 publications
(35 citation statements)
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“…A plot of   versus   is shown in Fig. S4 in the ESM, in which a single semicircle is denoted as a Cole-Cole semicircle, indicating a Debye relaxation process [59]. There are three semicircles over the entire curve.…”
Section: Emu/g) the Fe 3 O 4 @ N-doped Carbon Nanochains Possess A Hmentioning
confidence: 99%
“…A plot of   versus   is shown in Fig. S4 in the ESM, in which a single semicircle is denoted as a Cole-Cole semicircle, indicating a Debye relaxation process [59]. There are three semicircles over the entire curve.…”
Section: Emu/g) the Fe 3 O 4 @ N-doped Carbon Nanochains Possess A Hmentioning
confidence: 99%
“…Each semicircle is associated with one Debye relaxation process. 45 Fig. 7a-c shows the 3 0 -3 00 patterns of the Fe 2 O 3 /N-GN/CNTs, Fe 2 O 3 /N-GN, and Fe 2 O 3 /GN samples.…”
Section: Magnetic Propertiesmentioning
confidence: 99%
“…According to Debye dipolar relaxation model, 44 the relation of real parts ( ε ′) and imaginary parts ( ε ″) of permittivity can be expressed as the following equation:)(εεs+ε22+(ε)2=)(εsε22,where ε s and ε ∞ are the static permittivity and relative dielectric permittivity at the high‐frequency limit, respectively. The curve of ε ′ vs. ε ″ should be a semicircle (Cole‐Cole semicircle) and each semicircle represents one Debye dipolar relaxation process 45 . As shown in Figure 8A, distinct semicircles are presented for the corresponding four samples, demonstrating the existence of Debye dipolar relaxation and good permittivity dissipation capacity.…”
Section: Resultsmentioning
confidence: 90%