2019
DOI: 10.1007/s10208-019-09442-y
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Computing the Interleaving Distance is NP-Hard

Abstract: We show that computing the interleaving distance between two multi-graded persistence modules is NP-hard. More precisely, we show that deciding whether two modules are 1-interleaved is NP-complete, already for bigraded, interval decomposable modules. Our proof is based on previous work showing that a constrained matrix invertibility problem can be reduced to the interleaving distance computation of a special type of persistence modules. We show that this matrix invertibility problem is NP-complete. We also giv… Show more

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Cited by 25 publications
(26 citation statements)
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“…Consider any two constant DMSs γ X ≡ (X , d X ) and γ Y ≡ (Y , d Y ). Then, for any k ∈ Z + , inequality (7) reduces to:…”
Section: Relationship With Standard Stability Theoremsmentioning
confidence: 99%
See 3 more Smart Citations
“…Consider any two constant DMSs γ X ≡ (X , d X ) and γ Y ≡ (Y , d Y ). Then, for any k ∈ Z + , inequality (7) reduces to:…”
Section: Relationship With Standard Stability Theoremsmentioning
confidence: 99%
“…Given δ > 0, deciding whether d Vec I (M , N ) ≤ δ is in general NP-hard [7,8]. In Theorem 6.2, substituting the comparison of M and N with that of rk(M ) and rk(N ) results in doubling of the underlying dimension of the interleaving distance.…”
Section: Given Anymentioning
confidence: 99%
See 2 more Smart Citations
“…However, bi-filtrations still admit meaningful distance measures, which lead to the notion of closeness of two bi-filtrations. The most prominent such distance is the interleaving distance [39], which, however, has recently been proved to be NP-complete to compute and approximate [8]. Computationally attractive alternatives are (multi-parameter) bottleneck distance [22] and the matching distance [5,35], which compares the persistence diagrams along all slices (appropriately weighted) and picks the worst discrepancy as the distance of the bi-filtrations.…”
Section: Introductionmentioning
confidence: 99%