2012
DOI: 10.1007/s00440-012-0423-6
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Concentration and convergence rates for spectral measures of random matrices

Abstract: The topic of this paper is the typical behavior of the spectral measures of large random matrices drawn from several ensembles of interest, including in particular matrices drawn from Haar measure on the classical Lie groups, random compressions of random Hermitian matrices, and the so-called random sum of two independent random matrices. In each case, we estimate the expected Wasserstein distance from the empirical spectral measure to a deterministic reference measure, and prove a concentration result for tha… Show more

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Cited by 36 publications
(41 citation statements)
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“…This is an improvement of Meckes and Meckes' rate of convergence obtained in [16]. Note however that the distance studied in [16] is the expected 1-Wasserstein distance between L N and its mean instead of ρ sc .…”
Section: Proposition 13 There Exists a Universal Constantmentioning
confidence: 58%
See 2 more Smart Citations
“…This is an improvement of Meckes and Meckes' rate of convergence obtained in [16]. Note however that the distance studied in [16] is the expected 1-Wasserstein distance between L N and its mean instead of ρ sc .…”
Section: Proposition 13 There Exists a Universal Constantmentioning
confidence: 58%
“…Note however that the distance studied in [16] is the expected 1-Wasserstein distance between L N and its mean instead of ρ sc . The rate of convergence in 1-Wasserstein distance can be furthermore compared to the rate of convergence in Kolmogorov distance.…”
Section: Proposition 13 There Exists a Universal Constantmentioning
confidence: 99%
See 1 more Smart Citation
“…The required mixed moments of entries of random orthogonal matrices can also be found in [5]. For the Poincaré inequality estimate, one must condition on the coset of SO (n) within O (n); for similar arguments, see, e.g., [30]. The required spectral gap estimate on SO (n) can be found in [40].…”
Section: Proofs Of the Main Resultsmentioning
confidence: 99%
“…Suppose now that Λ n op = o(n). Then Λ n 2 4 ≤ Λ n HS √ Λ nop = nσ n Λ n op , and so by (29) Next, by (30), for each i, U → a ii is a 2 Λ op -Lipschitz function on U (n), and so (24) It is well known that E max 1≤i≤d g i ≥ c √ log d. If we assume now that Λ n op ≤ K √ n then choosing d = ⌊ √ n⌋ completes the proof.…”
Section: Now For Any I Amentioning
confidence: 95%