“…Let MS = {n ∈ N | n = 2 2k (2r + 1) − 1, k ≥ 1, r ≥ 0} be a subset of the set of all odd integers [31]. Show that (a) M S n ≡ 1 (mod 2), if either n ≡ 0 (mod 2) or n ∈ MS n , (b) M S n ≡ 0 (mod 2), if n is an odd integer and n / ∈ MS. Show that P n (0, α, β) α α=0 = N n−1 (β + 1), where as before, N n (t) denotes the Narayana polynomial.…”