2022
DOI: 10.3390/photonics9050310
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Contribution of New Three-Dimensional Code Based on the VWZCC Code Extension in Eliminating Multiple Access Interference in Optical CDMA Networks

Abstract: In order to solve the problem of one-dimensional code length, two-dimensional code spatial length, phase induced intensity noise PIIN effect, improved system capacity, and increased the number of simultaneous users, a new three-dimensional spectral/time/spatial variable weight zero cross correlation code for non-coherent spectral amplitude coding-optical code division multiple access (3D-VWZCC-SAC-OCDMA) is proposed in this paper. Its construction is based on a one-dimensional (1D) spectral sequence and two-di… Show more

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Cited by 8 publications
(12 citation statements)
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“…An example of the 3D‐SW code words is shown in Table 2 for (K1$$ {K}_1 $$ = 2, K2$$ {K}_2 $$ = 3,0.25emK3$$ {K}_3 $$ = 2), while, Figure 1 shows the graphical depiction of 3D‐SW code. Hence, the three‐dimensional SW code is expressed as follows 2 : Bg,h,lgoodbreak=XgTYhZl.$$ {B}_{g,h,l}={X}_g^T{Y}_h{Z}_l. $$ …”
Section: Three‐dimensional Codingmentioning
confidence: 99%
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“…An example of the 3D‐SW code words is shown in Table 2 for (K1$$ {K}_1 $$ = 2, K2$$ {K}_2 $$ = 3,0.25emK3$$ {K}_3 $$ = 2), while, Figure 1 shows the graphical depiction of 3D‐SW code. Hence, the three‐dimensional SW code is expressed as follows 2 : Bg,h,lgoodbreak=XgTYhZl.$$ {B}_{g,h,l}={X}_g^T{Y}_h{Z}_l. $$ …”
Section: Three‐dimensional Codingmentioning
confidence: 99%
“…To further clarify the cross‐correlation of 3D‐SW coding feature, the characteristic matrices Bfalse(dfalse)=Bfalse(0false),Bfalse(1false),Bfalse(7false)$$ {B}^{(d)}={B}^{(0)},{B}^{(1)},\dots {B}^{(7)} $$ are provided as follows 2 : Bfalse(dfalse)goodbreak={Bfalse(0false)goodbreak=XTY0.25emZBfalse(1false)goodbreak=XTtrueY0.25emZB(2)=trueXTYZB(3)=trueXTYZ0.25em{Bfalse(4false)goodbreak=XTY0.25emtrueZBfalse(5false)goodbreak=XTtrueY0.25emtrueZB(6)=trueXTYZB(7)=trueXTYZ$$ {B}^{(d)}=\left\{\begin{array}{c}{B}^{(0)}={X}^TY\ Z\\ {}{B}^{(1)}={X}^T\overline{Y}\ Z\\ {}\begin{array}{c}{B}^{(2)}={\overline{X}}^TY\ Z\\ {}{B}^{(3)}={\overline{X}}^T\overline{Y}\ Z\end{array}\end{array}\right.\ \left\{\begin{array}{c}{B}^{(4)}={X}^TY\ \overline{Z}\\ {}{B}^{(5)}={X}^T\overline{Y}\ \overline{Z}\\ {}\begin{array}{c}{B}^{(6)}={\overline{X}}^TY\ \overline{Z}\\ {}{B}^{(7)}={\overline{X}}^T\overline{Y}\ \overline{Z}\end{array}\end{array}\right. $$ where XT$$ {X}^T $$…”
Section: Three‐dimensional Codingmentioning
confidence: 99%
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