2019
DOI: 10.1515/jnma-2017-0073
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Convergence of explicitly coupled simulation tools (co-simulations)

Abstract: In engineering, it is a common desire to couple existing simulation tools together into one big system by passing information from subsystems as parameters into the subsystems under influence. As executed at fixed time points, this data exchange gives the global method a strong explicit component. Globally, such an explicit cosimulation schemes exchange time step can be seen as a step of an one-step method which is explicit in some solution components. Exploiting this structure, we give a convergence proof for… Show more

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Cited by 6 publications
(18 citation statements)
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“…The energy for this graph by using equation (14) is equal to 28.3401 (sum of singular values is equal to 7.9352). If the matrix is symmetrized, then the energy for this graph by using equation (14) is equal to 33.9041 (sum of singular values is equal to 9.4931).…”
Section: High Complexity Architecturementioning
confidence: 99%
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“…The energy for this graph by using equation (14) is equal to 28.3401 (sum of singular values is equal to 7.9352). If the matrix is symmetrized, then the energy for this graph by using equation (14) is equal to 33.9041 (sum of singular values is equal to 9.4931).…”
Section: High Complexity Architecturementioning
confidence: 99%
“…For example, these cycles can give rise to positive feedback loops [13] which lead to system instabilities. Cycles in engineering systems also make design and analysis challenging from a simulation convergence perspective [14,15].…”
Section: Introductionmentioning
confidence: 99%
“…The coupling equations (9) -(10) together with the algebraic equations (6) and (8) of the subsystems form a global system of algebraic equations. If the graph of the information flow through the subsystems has no loops and one applies an according Gauss-Seidel scheme, then the exchanged data is consistent in the sense that the equations (9), (10), (6) and (8) are fulfilled -in the general case they are not if one just solves (9), (10) with respect to the input.…”
Section: Making Inputs Consistentmentioning
confidence: 99%
“…S 1 :ẋ 1 = f 1 (x 1 , z 1 , u 12 ) (5) 0 = g 1 (x 1 , z 1 , u 12 ) (6) S 2 :ẋ 2 = f 2 (x 2 , z 2 , u 21 ) (7) 0 = g 2 (x 2 , z 2 , u 21 ) (8) where u i are given by coupling conditions that have to be fulfilled at exchange times T k 0 = h 21 (x 1 , z 1 , u 21 ) (9) 0 = h 12 (x 2 , z 2 , u 12 )…”
Section: Introductionmentioning
confidence: 99%
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