“…It is easy to see that this holds for k ∈ {2, 3, 4, 5}. However, in a short note the second author proved that σ 3 0 (k) ≥ 2k + 3 for all even k ≥ 6, see [5]. Cui and the first author [2] expanded on this and gave a full description of the values of σ 0 (k) and σ 3 0 (k) for all k; in particular, they showed that σ 0 (k) = σ 3 0 (k) = 2k + 3 for all k ≥ 10.…”