2022
DOI: 10.1088/1742-6596/2312/1/012018
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Damage Prediction of Pre-cracked High-Pressure Pipelines

Abstract: Due to the increasing need to transport fluids, the use of industrial pipes and their sustainability is a crucial aspect to address. The motive of this work is to predict the behaviour of a pre-cracked pipeline under internal and external pressure using Finite element simulation. An intermediate range of pressure conditions has been selected to analyse the dispersal of normalized stress intensity factor along a semi elliptical crack front for a predefined crack geometry. This work also presents a comparative s… Show more

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“…$$ Now from the expressions of (13)–(15) and (34)–(36), we get the form of Burgers equation as expressed below φfalse(1false)τgoodbreak+Aφfalse(1false)φfalse(1false)ζgoodbreak=C2φfalse(1false)ζ2,$$ \frac{\partial {\varphi}^{(1)}}{\partial \tau }+A{\varphi}^{(1)}\frac{\partial {\varphi}^{(1)}}{\partial \zeta }=C\frac{\partial^2{\varphi}^{(1)}}{\partial {\zeta}^2}, $$ where A$$ A $$ and C$$ C $$ denote the nonlinear and dissipation coefficients respectively, which are given by Agoodbreak=()Vp2goodbreak−σlz222Vplz2[]2Vp2lz4()Vp2goodbreak−σlz23goodbreak−(1goodbreak+μ),$$ A=\frac{{\left({V}_p^2-\sigma {l}_z^2\right)}^2}{2{V}_p{l}_z^2}\left[\frac{2{V}_p^2{l}_z^4}{{\left({V}_p^2-\sigma {l}_z^2\right)}^3}-\left(1+\mu \right)\right], $$ Cgoodbreak=η2.$$ C=\frac{\eta }{2}. $$ Using the same assumptions and procedures as in Section 3, we obtain the solution to the shock wave shown below [ 63 ] …”
Section: Burgers Equation and Solutionmentioning
confidence: 99%
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“…$$ Now from the expressions of (13)–(15) and (34)–(36), we get the form of Burgers equation as expressed below φfalse(1false)τgoodbreak+Aφfalse(1false)φfalse(1false)ζgoodbreak=C2φfalse(1false)ζ2,$$ \frac{\partial {\varphi}^{(1)}}{\partial \tau }+A{\varphi}^{(1)}\frac{\partial {\varphi}^{(1)}}{\partial \zeta }=C\frac{\partial^2{\varphi}^{(1)}}{\partial {\zeta}^2}, $$ where A$$ A $$ and C$$ C $$ denote the nonlinear and dissipation coefficients respectively, which are given by Agoodbreak=()Vp2goodbreak−σlz222Vplz2[]2Vp2lz4()Vp2goodbreak−σlz23goodbreak−(1goodbreak+μ),$$ A=\frac{{\left({V}_p^2-\sigma {l}_z^2\right)}^2}{2{V}_p{l}_z^2}\left[\frac{2{V}_p^2{l}_z^4}{{\left({V}_p^2-\sigma {l}_z^2\right)}^3}-\left(1+\mu \right)\right], $$ Cgoodbreak=η2.$$ C=\frac{\eta }{2}. $$ Using the same assumptions and procedures as in Section 3, we obtain the solution to the shock wave shown below [ 63 ] …”
Section: Burgers Equation and Solutionmentioning
confidence: 99%
“…Using the same assumptions and procedures as in Section 3, we obtain the solution to the shock wave shown below [63] 𝜙 (1) = 𝜓…”
Section: Burgers Equation and Solutionmentioning
confidence: 99%