“…Thus we have, from Proposition 2.1 (5), that H n (A) = i * (H n (X)) = i * (G n (X, r, A)) ⊂ G n (A, ri, A) = G n (A) and A is a G -space. (2) We show that H n (X) ⊂ G n (X) for all n. We obtain, from Proposition 2.1 (1), that H n (X) = G n (X, r, A) ⊂ G n (X, ir, X) = G n (X, 1, X) = G n (X). Thus we know that X is a G -space.…”