2014
DOI: 10.1016/j.corsci.2014.06.008
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Degradation behaviour of AZ80E magnesium alloy exposed to phosphate buffer saline medium

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Cited by 35 publications
(10 citation statements)
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“…In contrast, the HP Mg discs in Group 0 suffered severe corrosion and were almost depleted. Due to the great potential difference, which is −1.6 V vs SCE for pure Mg 23 and −0.4 V vs SCE for Ti in PBS 24 , galvanic corrosion occurred and significantly accelerated the corrosion of Mg. The SEM results demonstrated that there was a large area that had non-uniform degradation ( Fig.…”
Section: Resultsmentioning
confidence: 99%
“…In contrast, the HP Mg discs in Group 0 suffered severe corrosion and were almost depleted. Due to the great potential difference, which is −1.6 V vs SCE for pure Mg 23 and −0.4 V vs SCE for Ti in PBS 24 , galvanic corrosion occurred and significantly accelerated the corrosion of Mg. The SEM results demonstrated that there was a large area that had non-uniform degradation ( Fig.…”
Section: Resultsmentioning
confidence: 99%
“…Initial testing used immersion conditions in simple NaCl solutions, but these were found to be inappropriate [42]. Subsequently, a wide range of solutions and methodologies have been explored [36,[43][44][45][46], each with advantages and limitations, although some studies still continue to use NaCl solutions [47]. Table 1 provides a comparison of the constituent elements of several commonly used in vitro immersion solution [24,[48][49][50].…”
Section: Variability Of In Vitro Testing and The Need For Standardisamentioning
confidence: 99%
“…The W element is serially connected with the charge transfer resistance ( R ct ) and the two are in parallel with a constant phase element (CPE) that replaces the ideal double‐layer capacitance ( C dl ). The frequency‐independent admittance ( Q ) of the CPE has an empirical exponent (0≤ α ≤1) utilized to express its deviation from the ideal behavior due to surface heterogeneity [39, 40] and related to its impedance value ( Z CPE ) by the expression: Z CPE =1/ Q jωα ${{\left(j\omega \right)}^{\alpha }}$ , where ω=2πf ${\omega =2\pi f}$ is the angular frequency (in rad s −1 ), f is the ac signal frequency (in s −1 ) and j=-11/2 ${j=-{1}^{{ 1/2 }}}$ is the imaginary number. At ω ${\omega }$ =1, 1/ C dl will be equal to 1/ Q [40].…”
Section: Resultsmentioning
confidence: 99%