1977
DOI: 10.1016/0020-1650(77)80074-3
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Determination of oxidation potential of the pair Fm2+/Fm3+

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1983
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Cited by 20 publications
(7 citation statements)
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“…Moreover, on the basis of chemical data, redox potential of the fermium 3/2 reaction should be between −1.47 and −0.8 V [31], and finally, close to the ytterbium 3/2 couple (±0.02 V) [32].…”
Section: Existence Of Low Oxidation States Of Lanthanides and Actinidmentioning
confidence: 99%
“…Moreover, on the basis of chemical data, redox potential of the fermium 3/2 reaction should be between −1.47 and −0.8 V [31], and finally, close to the ytterbium 3/2 couple (±0.02 V) [32].…”
Section: Existence Of Low Oxidation States Of Lanthanides and Actinidmentioning
confidence: 99%
“…But its direct production by Cm(III) oxidation is difficult due to the high potential of the Cm(IV)/Cm(III) pair [151,152]. The stability of +2 state of oxidation on the whole increases with rising TPE atomic number [151], and the Fm(III)/Fm(II) pair has the same oxidation potential as the Yb(III)/Yb(II) pair [153], It has been shown [154] that Fm(III) can be reduced to Fm(II) by electrolysis on mercury cathode.…”
Section: Isotopes and Their Propertiesmentioning
confidence: 99%
“…The results for Fm may be expressed as follows: to -1.55 V relative to the standard Pt, H 2 ¡ H + electrode. Later work [74] by these scientists narrowed the range to between -0.64 and -1.15V and, most recently, they were able to estimate the potential was the same as the Yb 3+ Yb 2 + couple within 0.02 V, or -1.15 V [75,76], This estimate was based on measuring the ratio of Fm(III) to Fm(II) during the cocrystallization of Fm(II) with SrCl 2 while changing the ratio of Yb(II)/Yb(III) in each experiment. The difference between the standard potentials of Fm and Yb is then easily determined from the Nernst equation.…”
Section: Few Atom Chemistrymentioning
confidence: 99%