“…then Γ = Γ {1,2,4,7} ∪Γ {3} ∪Γ {5,6} and Γ = Γ {1,2,4,7} ∪ Γ {3,5,6} . Moreover Γ {1,2,4,7} is the tableau of X = P (0)⊕P (3, 5, 6)⊕E (6) , Γ {3} is the tableau of P (4), Γ {5,6} is the tableau of P (2, 1)⊕E (2) and Γ {3,5,6} is the tableau of D((1, 2, 4), ())⊕E (2) . By lemma 6.1 there exists the following short exact sequence: 0 → P (4) → D((1, 2, 4), ()) → P (2) → 0, so we have also the short exact sequence:…”