“…We conclude that, owing to the parallelism of the residue operations, this complexity measure will simply be equal to the summation of the corresponding memory sizes taken over all moduli in the system. This conclusion makes Table III directly applicable to This inequality, easily verifiable using Table III, has been established in somewhat different context in [20]. As an example, if M = 35, Ml = 7, MZ = 5, and D = 2, then from Table III we have L@(35, 2) = 2975, Le(35, 2) = 2886, L@(7, 2) + L@(5, 2) = 63 + 25 = 88, and Le(7, 2) + L@(5, 2) = 54 + 20 = 74.…”