“…Upon substitution of C = 6, R = 2, ϕ = 2, and I = 1 into eq , we calculate F = 6 – 2 – 2 – 1 + 2 = 3. In all cases where the metal exhibits the single oxidation state, Z +, the corresponding oxide, M x O y (s), exhibits a critical solubility effect when reacting with IBA/H 2 O. ,− As the metals, M Z + , have included copper, cobalt, nickel, tin, iron, aluminum, manganese, cerium, and indium, the existence of the metal oxide solubility critical effect would seem to be independent of the position of the metal in the periodic table.…”