“…Finally, taking similar steps to the second integral in equality (8) , where θBθU 4π 2 ∈ (0, 1], T 1+T ∈ (0, 1) and ρ(T, β 2 ) ∈ R + . Then we have θBθU For the constrained ASE given in (5), it is obvious that the second term inside the integral monotonically decreases w.r.t θB θU 4π 2 . Denote the partial derivative of the first term w.r.t θB θU 4π 2 by A 1 , and we have: where θB θU 4π 2 ∈ (0, 1], e t −1 e t ∈ (0, 1) and ρ(e t − 1, β 2 ) ∈ R + .…”