2019
DOI: 10.1016/j.physa.2019.04.104
|View full text |Cite
|
Sign up to set email alerts
|

Dynamic behaviors of a predator–prey model perturbed by a complex type of noises

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
4
1

Citation Types

0
7
0

Year Published

2019
2019
2024
2024

Publication Types

Select...
5

Relationship

1
4

Authors

Journals

citations
Cited by 5 publications
(7 citation statements)
references
References 26 publications
0
7
0
Order By: Relevance
“…Our equation differs from the aforementioned equation (A) examined in (Guo et al, 2019). To investigate the extinction property of our method, we will start by considering the equation on the boundary, truex˜()tgoodbreak=truex˜()t{}rugoodbreak+autruex˜()tgoodbreak+σutruex˜()titalicdB()t,$$ \tilde{x}(t)=\tilde{x}(t)\left\{{r}^u+{a}^u\tilde{x}(t)\right\}+{\sigma}^u\tilde{x}(t) dB(t), $$ with initial value truex˜()0=x()0>0$$ \tilde{x}(0)=x(0)>0 $$ almost surely, following the lemma 2.2* and solving the Fokker–Planck equation in (Guo et al, 2019) we have the density of the stationary distribution of the process truex˜()t$$ \tilde{x}(t) $$, ϕ()xgoodbreak=lqnormalΓ()qxq1eitaliclx,x>0,$$ \phi (x)=\frac{l^q}{\Gamma (q)}{x}^{q-1}{e}^{- lx},x>0, $$ where l=2au/σu2$$ l=2{a}^u/{\left({\sigma}^u\right)}^2 $$, q=2ru/σu21>0$$ q=2{r}^u/{\left({\sigma}^u\right)}^2-1>0 $$ and normalΓ()$$ \Gamma \left(\cdot \right) $$ is the Gamma function. By strong ergodicity theorem, we can deduce that for any measurabl...…”
Section: Extinctionmentioning
confidence: 78%
See 4 more Smart Citations
“…Our equation differs from the aforementioned equation (A) examined in (Guo et al, 2019). To investigate the extinction property of our method, we will start by considering the equation on the boundary, truex˜()tgoodbreak=truex˜()t{}rugoodbreak+autruex˜()tgoodbreak+σutruex˜()titalicdB()t,$$ \tilde{x}(t)=\tilde{x}(t)\left\{{r}^u+{a}^u\tilde{x}(t)\right\}+{\sigma}^u\tilde{x}(t) dB(t), $$ with initial value truex˜()0=x()0>0$$ \tilde{x}(0)=x(0)>0 $$ almost surely, following the lemma 2.2* and solving the Fokker–Planck equation in (Guo et al, 2019) we have the density of the stationary distribution of the process truex˜()t$$ \tilde{x}(t) $$, ϕ()xgoodbreak=lqnormalΓ()qxq1eitaliclx,x>0,$$ \phi (x)=\frac{l^q}{\Gamma (q)}{x}^{q-1}{e}^{- lx},x>0, $$ where l=2au/σu2$$ l=2{a}^u/{\left({\sigma}^u\right)}^2 $$, q=2ru/σu21>0$$ q=2{r}^u/{\left({\sigma}^u\right)}^2-1>0 $$ and normalΓ()$$ \Gamma \left(\cdot \right) $$ is the Gamma function. By strong ergodicity theorem, we can deduce that for any measurabl...…”
Section: Extinctionmentioning
confidence: 78%
“…To establish the extinction property, it is essential to introduce certain preliminaries. Let us begin by restating the lemma 2.2 in (Guo et al, 2019),…”
Section: Extinctionmentioning
confidence: 99%
See 3 more Smart Citations