2019
DOI: 10.1186/s13662-019-1982-y
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Existence results of nonlocal boundary value problem for a nonlinear fractional differential coupled system involving fractional order impulses

Abstract: In this paper, we study the nonlocal boundary value problem for a nonlinear fractional differential coupled system with fractional order impulses. Applying Nonlinear Alternative of Leray-Schauder, we obtain some new existence results for this system. As application, an interesting example is given to illustrate the effectiveness of our main result.

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Cited by 13 publications
(2 citation statements)
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“…In particular, impulsive nonlocal boundary conditions are finite combinations of classical boundary problems and short-term perturbations whose duration can be negligible in comparison with the duration of the system process. They have advantages over classical boundary problems, because they can be used to model phenomena that cannot be modeled by traditional boundary problems; the reader can refer to [6,19] and references therein. The applications of many forms of fixed point theorems have been used extensively for investigations of existence and uniqueness problems of impulsive nonlocal fractional differential equations.…”
Section: Introductionmentioning
confidence: 99%
“…In particular, impulsive nonlocal boundary conditions are finite combinations of classical boundary problems and short-term perturbations whose duration can be negligible in comparison with the duration of the system process. They have advantages over classical boundary problems, because they can be used to model phenomena that cannot be modeled by traditional boundary problems; the reader can refer to [6,19] and references therein. The applications of many forms of fixed point theorems have been used extensively for investigations of existence and uniqueness problems of impulsive nonlocal fractional differential equations.…”
Section: Introductionmentioning
confidence: 99%
“…Using Lemma 1, Example 3 (iv), on (21) and denoting the Laplace transform L {y(t)} = Y(s), we obtain Y(s) = n!s 3σ (s − 1) n+1 (cs 3σ + bs 2σ + as σ + 1) . (22) For σ = 1/3, Equation (22) becomes…”
mentioning
confidence: 99%