1998
DOI: 10.1103/physrevb.57.4681
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Formulation of the optical response in semiconductors and quantum-confined structures

Abstract: Based on the Green's-function formalism, we present an approach to the linear and nonlinear optical properties of semiconductors and their heterostructures. Starting from the Bethe-Salpeter equation ͓as provided in Schmitt-Rink, Ell, and Haug, Phys. Rev. B 33, 1183 ͑1986͔͒, we obtain closed-form expressions for the interband density of states in the presence of a carrier plasma of arbitrary density and in quasiequilibrium. Focusing on two-dimensional heterostructures, we discuss both the exciton resonances and… Show more

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Cited by 10 publications
(8 citation statements)
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“…͑2͒ a renormalization term, treating it as in Ref. 16. The resulting equations resulted unchanged, except for the self-energy correction to E 0 wherever it appears.…”
Section: ͑2͒mentioning
confidence: 99%
See 1 more Smart Citation
“…͑2͒ a renormalization term, treating it as in Ref. 16. The resulting equations resulted unchanged, except for the self-energy correction to E 0 wherever it appears.…”
Section: ͑2͒mentioning
confidence: 99%
“…We can write q as ͱ q 2 , being it real and positively defined. In this way, following the method developed in previous works, 16,22 we can extend the integration limit to the negative real axis, dividing the result by two. Then we can extend the integration to the complex plane, adding to the integration path a half-circle at infinity in upper half plane, yielding a vanishing contribution.…”
Section: ͑20͒mentioning
confidence: 99%
“…(25) with d ab m ¼ 0). Using these parameters we calculate the bound state energies (see [12]) and scattering phase shifts (see [10]) with the interaction potentials, Eqs. (10), (11).…”
Section: Resultsmentioning
confidence: 99%
“…We can write q as ͱq 2 , being it real and positively defined. In this way, following the method developed in our previous works, 23,24 we can consider the substitution zϭqϪk, extend the integration limit to the negative real axis, dividing the result by 2. Then we extend the integration to the complex plane, adding to the integration path a half circle at infinity in upper half plane, yielding a vanishing contribution.…”
Section: ͑22͒mentioning
confidence: 99%