2018
DOI: 10.1088/1755-1315/170/4/042088
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Forward and Inverse Kinematics for a Novel Double Scara Robot

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Cited by 5 publications
(4 citation statements)
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“…In the second joint matrix there are two parameters represented with one homogeneous matrix each, a rotational matrix in the axis Z 𝑅 𝑧𝑖 (πœƒ 𝑖 ) one translation in the X-axis 𝑇 π‘₯π‘–βˆ’1 (π‘Ž π‘–βˆ’1 ) and a last translation in the Z-axis 𝑇 𝑧𝑖 (𝑑 𝑖 ) resulting in ( 4) and (5).…”
Section: Control System Based On Kinematicsmentioning
confidence: 99%
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“…In the second joint matrix there are two parameters represented with one homogeneous matrix each, a rotational matrix in the axis Z 𝑅 𝑧𝑖 (πœƒ 𝑖 ) one translation in the X-axis 𝑇 π‘₯π‘–βˆ’1 (π‘Ž π‘–βˆ’1 ) and a last translation in the Z-axis 𝑇 𝑧𝑖 (𝑑 𝑖 ) resulting in ( 4) and (5).…”
Section: Control System Based On Kinematicsmentioning
confidence: 99%
“…Any application in which a robotic arm is used requires the design of a trajectory, in which the behavior of the robot is planned according to the work area to perform its task reaching a suitable position and orientation for the end effector [4]. Most of the time the structure of the robotic arms used is in series due to the lower complexity in kinematics and the advantages of a larger working space compared to the closed structure [5] due to close structures such as [6]. The inverse kinematics is the opposite seeks to find the positions and orientation of the links or body of the robot with respect to a reference that is the end effector [7].…”
Section: Introductionmentioning
confidence: 99%
“…Kinematic calculations can be divided into two types: forward and inverse kinematics. Forward kinematics calculate the position and orientation of the end effector from the given joint variables [5], while inverse kinematics calculate the set of joint angles required for the robot to achieve the desired position. To obtain the points of interest, a geometric method was chosen [6,7], and the Denavit-Hartenberg method was used for forward kinematics, while the inverse kinematic model was found from the homogeneous transformation matrix.…”
Section: Introductionmentioning
confidence: 99%
“…We proceed to find the equations of the coordinates of the positioning point with respect to ΞΈ1 and considering the established coordinate axis. 𝑋 π‘π‘œπ‘  = 𝐿 5 π‘π‘œπ‘  π‘π‘œπ‘  (90 βˆ’ πœƒ 3 ) βˆ’ 𝐿 3 π‘Œ π‘π‘œπ‘  = 𝐿 4 𝑠𝑖𝑛 𝑠𝑖𝑛 (πœƒ 1 ) βˆ’ [𝐿 2 βˆ’ 𝐿 5 𝑠𝑖𝑛 𝑠𝑖𝑛 (90 βˆ’ πœƒ 3 ) ]π‘π‘œπ‘ πœƒ 1 𝑍 π‘π‘œπ‘  = 𝐿 1 + [𝐿 2 βˆ’ 𝐿 5 𝑠𝑖𝑛 𝑠𝑖𝑛 (90 βˆ’ πœƒ 3 ) ]π‘ π‘–π‘›πœƒ 1 + 𝐿 4 π‘π‘œπ‘ πœƒ 1(3) (4)(5)…”
mentioning
confidence: 99%