2021
DOI: 10.1007/s00365-021-09526-5
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Fourier Multipliers on a Vector-Valued Function Space

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Cited by 5 publications
(5 citation statements)
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“…Then m and 1 m are Fourier multipliers, see [22,Section 1.5.2] (B-scale), [22,Theorem,p. 75] (F -scale, p < ∞) and [15] (F -scale, p = ∞), and it follows that both (φ k ) k∈N 0 and the resolution of unity ( 1 m φ k ) k∈N 0 define equivalent (quasi-)norms.…”
Section: Function Spacesmentioning
confidence: 99%
See 1 more Smart Citation
“…Then m and 1 m are Fourier multipliers, see [22,Section 1.5.2] (B-scale), [22,Theorem,p. 75] (F -scale, p < ∞) and [15] (F -scale, p = ∞), and it follows that both (φ k ) k∈N 0 and the resolution of unity ( 1 m φ k ) k∈N 0 define equivalent (quasi-)norms.…”
Section: Function Spacesmentioning
confidence: 99%
“…Since f and g play symmetric roles, it is enough to consider the case p 1 = ∞. Then, by (15), p = ∞ and p 2 = 1, i.e. we need to prove that…”
Section: Theorem Letmentioning
confidence: 99%
“…Since one of p j 's is less or equal to 1, we benefit from the atomic decomposition for the Hardy space. Moreover, for other indices greater than 2, we employ the techniques of (variant) ϕ-transform, introduced by Frazier and Jawerth [8,9,10] and Park [26], which will be presented in Section 2. Then T σ (f 1 , f 2 , f 3 ) can be decomposed in the form…”
Section: Then the Two Estimatesmentioning
confidence: 99%
“…It is also known in [26] that Γ j f has a representation analogous to (2.7) with an equivalence similar to (2.8), while f = j∈Z Γ j f generally. Let θ := 2 n θ(2•) and θ j := 2 jn θ(…”
Section: 3mentioning
confidence: 99%
“…[18,Exercise 13.21]); this allows us to let θ → ∞ on the left-hand side of the previous inequality. For the right-hand side we use once more the dominated convergence theorem, which is applicable because of (15). Thus, we arrive at…”
mentioning
confidence: 99%