“…Now, let us assume that the supersymmetric factorization (38) is valid in this model and that supersymmetry is unbroken, with the superpotential W (y) being such that W (+∞) > 0 and W (−∞) < 0, as it happens in the φ 4 and sine-Gordon theories. In such a case, we can proceed backwards, i.e., we can reconstruct the kink and, to some extent, even the potential of the scalar field theory starting from the Hessian [36,37]. The reason is translational invariance, because this symmetry implies that H y has always a normalizable zero mode, the translational mode of the kink, given by f 0 = dψ K dy which, by virtue of unbroken supersymmetry, satisfies D y f 0 = 0.…”