2000
DOI: 10.1007/s002200050801
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Global Weak Solutions for a Shallow Water Equation

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Cited by 468 publications
(232 citation statements)
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“…Moreover, Camassa-Holm equation not only has global strong solutions, but also admits finite time blow-up solutions [9,12,13,59,17], and the blow-up occurs in the form of breaking waves, namely, the solution remains bounded but its slope becomes unbounded in finite time. On the other hand, it also has global weak solutions in H 1 (see [3,14,20,79]). The advantage of the Camassa-Holm equation in comparison with the KdV equation lies in the fact that the Camassa-Holm equation has peaked solitons and models the peculiar wave breaking phenomena (cf.…”
Section: Shouming Zhou Chunlai Mu and Liangchen Wangmentioning
confidence: 96%
“…Moreover, Camassa-Holm equation not only has global strong solutions, but also admits finite time blow-up solutions [9,12,13,59,17], and the blow-up occurs in the form of breaking waves, namely, the solution remains bounded but its slope becomes unbounded in finite time. On the other hand, it also has global weak solutions in H 1 (see [3,14,20,79]). The advantage of the Camassa-Holm equation in comparison with the KdV equation lies in the fact that the Camassa-Holm equation has peaked solitons and models the peculiar wave breaking phenomena (cf.…”
Section: Shouming Zhou Chunlai Mu and Liangchen Wangmentioning
confidence: 96%
“…More interestingly, it has global strong solutions [19,11,12] and also finite time blow-up solutions [19,20,11,12,21,13,16,17]. On the other hand, it has global weak solutions in H 1 (R) [22][23][24][25][26]. Finite propagation speed and persistence properties of solutions to the Camassa-Holm equation have been studied in [27,28].…”
Section: Introductionmentioning
confidence: 99%
“…To describe the peakons, one has to study weak solution to (1.1). In [9], it is proved that if u 0 ∈ H 1 (S) is such that (1−∂ 2 x )u 0 is a positive Radon measure with bounded total variation (e.g., u 0 = ϕ), then (1.1) has a unique solution u ∈ C([0, ∞); H 1 (S)) ∩ C 1 ([0, ∞); L 2 (S)), and H 0 , H 1 , and H 2 are conserved functionals. We would like to point out that if (1 − ∂ 2…”
Section: Commentsmentioning
confidence: 99%