1977
DOI: 10.1017/s0027763000022534
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Hartman’s theorem for hyperbolic sets

Abstract: Hartman proved that a diffeomorphism is topologically conjugate to a linear map on a neighbourhood of a hyperbolic fixed point ([3]). In this paper we study the topological conjugacy problem of a diffeomorphism on a neighbourhood of a hyperbolic set, and prove that for any hyperbolic set there is an arbitrarily slight extension to which a sub-shift of finite type is semi-conjugate.

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Cited by 4 publications
(4 citation statements)
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“…In particular, we have omitted a result concerning the existence and Hölder continuity of some conjugacies needed in section 4.3. The existence follows from the extension of the Hartman-Grobman Theorem mentioned above ( [16]), and it should be plausible at least that the conjugacies implied by this theorem are Hölder continuous (this is certainly true for the standard Hartman-Grobman Theorem). All the relevant details can be found in [21].…”
Section: Analytic Resultsmentioning
confidence: 98%
See 1 more Smart Citation
“…In particular, we have omitted a result concerning the existence and Hölder continuity of some conjugacies needed in section 4.3. The existence follows from the extension of the Hartman-Grobman Theorem mentioned above ( [16]), and it should be plausible at least that the conjugacies implied by this theorem are Hölder continuous (this is certainly true for the standard Hartman-Grobman Theorem). All the relevant details can be found in [21].…”
Section: Analytic Resultsmentioning
confidence: 98%
“…Instead, we introduce a semi-conjugacy whose properties are more amenable to analysis. A generalisation of the Hartman-Grobman Theorem ( [20,16,21]) and Condition 7 below, then provide this information.…”
Section: Analytic Resultsmentioning
confidence: 99%
“…ficiently large L But this is impossible by (1) and (2). Thus S o does not contain any periodic point of h.…”
Section: Proof Of the Main Theoremmentioning
confidence: 93%
“…Also, by (4.2), S o = p{σ*(a w ); w e (0,1), k ^ 0} 3 pjα^; M; 6 (0,1)}. By (1), (2), and (4.1), it is clear that p{a w ; w e (0,1)} is uncountable. Hence S o is an uncountable subset of M.…”
mentioning
confidence: 95%