“…• , δ even , δ even ] T = 1 10 −M 0,0 + 5M 1,0 + 10M 3,0 − 5M 4,0 + M 5,0 . Checking property (21) for the masks M 0,0 , M 1,0 and M even 2,0 , we notice that Y T M 0,0 = 0, Y T M 1,0 = 0 but Y T M even 2,0 = 0. Thus, we need to compute a new mask M 2,0 = [δ • , δ, δ ] T ensuring (21) in order to have a solution for system (17).…”