“…Interestingly, the reaction of [PtMe 2 (phen)] with 1,2-dibromoethane results in the formation of mononuclear complex trans-[PtI 2 Me 2 (phen)], binuclear complex [Pt 2 I 2 Me 4 {l-(CH 2 ) 2 }(phen) 2 ] and ethylene [6]. Also, the reaction of platinum(II) complex [PtMe 2 (bpy)] with X(CH 2 ) n X (n = 1, X = Cl; n = 4, X = Br) results in the formation of dimethylplatinum(IV) complexes [PtMe 2 X(CH 2 X)(bpy)] [7]. The reaction of [PtMe 2 (phen)] with CH 2 I 2 yields a mixture of cis and trans-[PtMe 2 I(CH 2 I)(phen)] and trans-[PtMe 2 I 2 (phen)] while it reacts with CH 2 ClI to afford a mixture of cis and trans-[PtMe 2 I 2 (phen)], cis and trans-[PtMe 2 I(CH 2 Cl)(phen)] and small amounts of cis and trans-[PtMe 2 Cl(CH 2 Cl)(phen)] via a free radical mechanism [8,9].…”