1961
DOI: 10.1115/1.3641706
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Investigation of Flat-Plate Hypersonic, Turbulent Boundary Layers With Heat Transfer

Abstract: Naturally turbulent boundary layers on a cooled flat plate have been investigated at several distances from the leading edge of the plate at a Mach number of 5.2 for three rates of steady-state heat transfer to the surface. Measurements of Pitot and static pressures and of total and wall temperatures made it possible to compute velocity profiles, static-temperature profiles, and boundary-layer parameters without resorting to assumptions. The data demonstrate that the Reynolds analogy between skin friction and … Show more

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Cited by 9 publications
(3 citation statements)
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“…The relations given in both references differ somewhat from equations (3) and (4). The present results have been compared with experimental skin friction coefficients of references (6), (9), (10), (11), (12), and (13) which cover the range of M l from 1.7 to 7.0 and (TT, -Tw)/TT, from 0.04 to 0.84. There is reasonable agreement between theory and experiment.…”
Section: Boundary-layer Parametersmentioning
confidence: 79%
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“…The relations given in both references differ somewhat from equations (3) and (4). The present results have been compared with experimental skin friction coefficients of references (6), (9), (10), (11), (12), and (13) which cover the range of M l from 1.7 to 7.0 and (TT, -Tw)/TT, from 0.04 to 0.84. There is reasonable agreement between theory and experiment.…”
Section: Boundary-layer Parametersmentioning
confidence: 79%
“…For Tw = constant and n = constant, the following result can be obtained from equations (12) and (13) …”
Section: Boundary-layer Parametersmentioning
confidence: 99%
“…The Winkler and Cha correlation equation for the skinfriction coefficient in a compressible, turbulent boundary layer is based on experimental data obtained in a hypersonic wind tunnel. 20 In terms of enthalpy, the Winkler and Cha equation may be written as (9) where c fi is that for incompressible flow and may be evaluated using Eq. (3).…”
Section: = [(H T /H E )} -L/(h W /H E ) B = (H T /Hj -I (5)mentioning
confidence: 99%