2008
DOI: 10.1039/b803181a
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Kinetics and mechanism of O–O bond cleavage in the reaction of [RuIII(edta)(H2O)]− with hydroperoxides in aqueous solution

Abstract: The reactions of [Ru(III)(edta)(H(2)O)](-) (1) (edta = ethylenediaminetetraacetate) with tert-butylhydroperoxide ((t)BuOOH) and potassium hydrogenpersulfate (KHSO(5)) were studied kinetically as a function of oxidant concentration and temperature (10-30 degrees C) at a fixed pH of 6.1 using stopped-flow techniques. Kinetic results were analyzed by using global kinetic analysis techniques. The reaction was found to consist of two steps involving the rapid formation of a [Ru(III)(edta)(OOR)](2-) intermediate, wh… Show more

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Cited by 21 publications
(13 citation statements)
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“…The findings of this work, together with those for the reaction of [Ru III (edta)(H 2 O)] À with ROOH (R ¼ H, t Bu, and SO À 4 ), strongly suggests that the formation of [(edta)Ru V (¼O)] À species in the reaction of 1 with S 2 O 2À 8 takes place through an alkali-cation-assisted outer-sphere electron-transfer process not via oxo-transfer as observed for ROOH [10,11].…”
Section: Resultsmentioning
confidence: 85%
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“…The findings of this work, together with those for the reaction of [Ru III (edta)(H 2 O)] À with ROOH (R ¼ H, t Bu, and SO À 4 ), strongly suggests that the formation of [(edta)Ru V (¼O)] À species in the reaction of 1 with S 2 O 2À 8 takes place through an alkali-cation-assisted outer-sphere electron-transfer process not via oxo-transfer as observed for ROOH [10,11].…”
Section: Resultsmentioning
confidence: 85%
“…Although [(edta)Ru V ¼O] À is the common major product in the reaction of 1 with S 2 O 2À 8 and other precursor oxidants, H 2 O 2 , t BuOOH, and KHSO 5 , above results rule out the possibility of a common mechanism. The reaction of 1 with ROOH (R ¼ H, t Bu, and SO À 3 ) proceeds via aquo-substitution leading to the formation of [(edta)Ru III (OOR)] 2À/3À , which subsequently undergo heterolytic cleavage of the O-O bond resulting in the formation of Ru(V)-oxo species [10,11]. The formation of Table 1.…”
Section: Resultsmentioning
confidence: 98%
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“…We have reported earlier that the reaction of [Ru III (edta)(H 2 O)] − with HSO 5 − results in the formation of the [Ru V (edta)O] − complex. However, [Ru III (edta)(H 2 O)] − reacts with HSO 5 − to produce [Ru V (edta)O] − at a considerably slower rate (7.0 M −1 s −1 at 25°C) than it reacts with SCN − (270 M −1 s −1 at 25°C ) to produce [Ru III (edta)(SCN)] 2− . The free [Ru III (edta)(H 2 O)] − generated at the end of the reaction (Eq.…”
Section: Resultsmentioning
confidence: 99%