2021
DOI: 10.48550/arxiv.2111.13255
|View full text |Cite
Preprint
|
Sign up to set email alerts
|

Knotted handlebodies in the 4-sphere and 5-ball

Abstract: For every integer g ≥ 2 we construct smooth 3-dimensional 1handlebodies H1 and H2 of genus g, which are properly embedded in B 5 with the same boundary, such that both H1 and H2 are smoothly boundary parallel and are homeomorphic rel boundary as 3-manifolds, yet H1 and H2 are not related by a topological, locally flat isotopy rel boundary.In other words, we construct 3-dimensional genus-g 1-handlebodies smoothly embedded in S 4 with the same boundary that are defined by the same cut systems of their boundary y… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...

Citation Types

0
2
0

Year Published

2022
2022
2022
2022

Publication Types

Select...
1

Relationship

0
1

Authors

Journals

citations
Cited by 1 publication
(2 citation statements)
references
References 10 publications
0
2
0
Order By: Relevance
“…We will work mostly in the smooth category, with a slight detour into the PL-category. The main argument for unknotting any B 3 is derived from the fact that any nonseparating S 3 in S 1 × S 3 extends to a smoothly embedded B 4 in S 1 × B 4 . This is a consequence of the classification of pseudoisotopies of S 1 × S 3 ( [5]).…”
mentioning
confidence: 99%
See 1 more Smart Citation
“…We will work mostly in the smooth category, with a slight detour into the PL-category. The main argument for unknotting any B 3 is derived from the fact that any nonseparating S 3 in S 1 × S 3 extends to a smoothly embedded B 4 in S 1 × B 4 . This is a consequence of the classification of pseudoisotopies of S 1 × S 3 ( [5]).…”
mentioning
confidence: 99%
“…As we are considering what happens in B 5 , take a collar neighborhood S 4 × I of the boundary and extend Y to Y× I. As U is the unknot, Y is diffeomorphic to S 1 × B 3 and Y × I is then diffeomorphic to S 1 × B4 , which in our given product structure is just (S 1 × B 3 ) × I. Now consider the 3-spheres, B × {0} ∪ U × I ∪ B × {1}.…”
mentioning
confidence: 99%