Abstract:In 1779 Euler proved that for every even n there exists a latin square of order n that has no orthogonal mate, and in 1944 Mann proved that for every n of the form 4k + 1, k ≥ 1, there exists a latin square of order n that has no orthogonal mate. Except for the two smallest cases, n = 3 and n = 7, it is not known whether a latin square of order n = 4k + 3 with no orthogonal mate exists or not. We complete the determination of all n for which there exists a mate-less latin square of order n by proving that, wit… Show more
Abstract:We prove that for all odd m ≥ 3 there exists a latin square of order 3m that contains an (m−1)×m latin subrectangle consisting of entries not in any transversal. We prove that for all even n ≥ 10 there exists a latin square of order n in which there is at least one transversal, but all transversals coincide on a single entry. A corollary is a new proof of the existence of a latin square without an orthogonal mate, for all odd orders n ≥ 11. Finally, we report on an extensive computational study of transversal-free entries and sets of disjoint transversals in the latin squares of order n ≤ 9. In particular, we count the number of species of each order that possess an orthogonal mate. q
Abstract:We prove that for all odd m ≥ 3 there exists a latin square of order 3m that contains an (m−1)×m latin subrectangle consisting of entries not in any transversal. We prove that for all even n ≥ 10 there exists a latin square of order n in which there is at least one transversal, but all transversals coincide on a single entry. A corollary is a new proof of the existence of a latin square without an orthogonal mate, for all odd orders n ≥ 11. Finally, we report on an extensive computational study of transversal-free entries and sets of disjoint transversals in the latin squares of order n ≤ 9. In particular, we count the number of species of each order that possess an orthogonal mate. q
“…After submitting this paper we received a preprint [6] in which Evans has independently obtained our Corollary 1.1 using a variation of our technique.…”
A latin square is a bachelor square if it does not possess an orthogonal mate; equivalently, it does not have a decomposition into disjoint transversals. We define a latin square to be a confirmed bachelor square if it contains an entry through which there is no transversal. We prove the existence of confirmed bachelor squares for all orders greater than three. This resolves the existence question for bachelor squares.
“…The general case for n = 4t +3 remained unsettled until two independently obtained results were simultaneously published in 2006. Those results, by Evans [11], and by Wanless and Webb [18], each conclude the existence of a bachelor latin square of order n for all n / ∈ {1, 3}. The actual result due to Wanless and Webb [18] is stated below in Theorem 1.6.…”
Section: Corollary 15mentioning
confidence: 86%
“…Other new general constructions of confirmed bachelor latin squares are described in [10]. We refer the reader to that article for a comparison of the known constructions for bachelor latin squares [10][11][12]18].…”
Section: Discussionmentioning
confidence: 99%
“…is a multiple of m. Lemma 2.1 is due, independently, to Egan and Wanless [8] and Evans [11]. It was applied in [18] to prove Theorem 1.6.…”
Section: Bachelor Latin Squares Of Odd Ordermentioning
Abstract:In a latin square of order n, a k-plex is a selection of kn entries in which each row, column, and symbol occurs k times. A 1-plex is also called a transversal. A k-plex is indivisible if it contains no c-plex for 0
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