1992
DOI: 10.1016/0021-8693(92)90158-i
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Lattice-ordered fields as convolution algebras

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Cited by 11 publications
(25 citation statements)
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“…For any PROOF. This result follows from [19,Proposition 7.2] One obvious question raised by this result is when the algebra of condition (i) is a field. Using the results of Section 3, we have the following partial answer to this question.…”
Section: Embeddings Of Lattice-ordered Fieldsmentioning
confidence: 78%
See 2 more Smart Citations
“…For any PROOF. This result follows from [19,Proposition 7.2] One obvious question raised by this result is when the algebra of condition (i) is a field. Using the results of Section 3, we have the following partial answer to this question.…”
Section: Embeddings Of Lattice-ordered Fieldsmentioning
confidence: 78%
“…Form the product n A T; for a € A and r e L, let a,r e]l A t be the vectors , {r a p), +, •), is a commutative ring with 7 = T as the multiplicative identity (cf. [4], [5], [13], [16], [20], [21], [22] [9], [13], [16], [17], [18], [19], [20], [21], [22]. When Ribenboim's convolution rings [20], [21], [22] are based on a group, they are a special case of this construction; he requires the supports to be locally inversely well-ordered and to have no infinite disjoint subsets.)…”
Section: Power Series Algebrasmentioning
confidence: 99%
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“…It is well known ( [2], [4], [5], [6]) that X T F is a field with respect to coordinatewise addition and to convolution as multiplication:…”
Section: Totally Ordered Subfields Of Partially Ordered Fieldsmentioning
confidence: 99%
“…It is well known that every -field L in which 1 > 0 has a maximal o-subfield M (L) (cf. [4], [7]). For archimedean -fields, Schwartz proved in [7] that even if 1 > 0, there is a subfield with properties similar to those of the o-subfields M (L).…”
Section: Introductionmentioning
confidence: 99%