1985
DOI: 10.1063/1.335023
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Magnetic scattering of x rays (invited)

Abstract: The scattering of x rays is used to determine the electric charge distribution in matter. Since x rays are electromagnetic radiation, we should expect that they will be sensitive not only to the charge distribution, but also to the magnetization density. That this is indeed the case has been pointed out and studied experimentally. In this paper the magnetic scattering is discussed in a way which allows consideration of the effects of electron binding. The cross section, compared with that for neutron scatterin… Show more

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Cited by 480 publications
(274 citation statements)
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“…For their derivation the quantity of interest is the transition rate probability W between the initial and final states of the excited atomic electrons, when they interact with light. The Hamiltonian of an atomic electron in a quantized electromagnetic field [169] can be split into contributions of the undisturbed electron system, free radiation field and interaction Hamiltonian, H = H 0 + H rad + H int , where…”
Section: Quantum Mechanical Descriptionmentioning
confidence: 99%
“…For their derivation the quantity of interest is the transition rate probability W between the initial and final states of the excited atomic electrons, when they interact with light. The Hamiltonian of an atomic electron in a quantized electromagnetic field [169] can be split into contributions of the undisturbed electron system, free radiation field and interaction Hamiltonian, H = H 0 + H rad + H int , where…”
Section: Quantum Mechanical Descriptionmentioning
confidence: 99%
“…Consequently, a non-resonant magnetic X-ray diffraction (NRMXD) experiment was performed at beam line I16, Diamond Light Source, UK. This technique exploits the dependence of the NRMXD cross-section on the direction of the magnetic moment with respect to the incident and scattered directions of the light and the X-ray polarization [16]. To minimize the fluorescent background, the incident x-ray beam was tuned to 7.835 keV, well below the copper and niobium K absorption edges.…”
mentioning
confidence: 99%
“…18,19,20 We summarize here the expression of the amplitude in a form suitable to the present calculation. The scattering geometry is shown in Fig.…”
Section: A Procedures Of Calculationmentioning
confidence: 99%