“…We observe that when s = •, α(f (1) ) = f (5) , α −1 (f (6) ) = f (8) , and the set T • {f (1) , f (2) , f (3) , f (4) , f (7) , f (8) } is independent, and when s = •, α −1 (f (11) ) = f (13) and the set T • {f (9) , f (10) , f (11) , f (12) } is independent. Thus, both T • and T • are transversals of F • and F • , respectively, and since T • and T • are mutually independent, we obtain T F T • ∪ T • as an admissible transversal of Fibonacci scales, its elements are shown in Figure 4.…”