2020
DOI: 10.1186/s13660-020-02396-8
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New inequalities between the inverse hyperbolic tangent and the analogue for corresponding functions

Abstract: In this paper, we present new inequalities which reveal further relationship for both the inverse tangent function $\arctan (x)$arctan(x) and the inverse hyperbolic function $\operatorname{arctanh}(x)$arctanh(x). At the same time, we give the analogue for inverse hyperbolic tangent and other corresponding functions.

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Cited by 8 publications
(2 citation statements)
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“…To prove (63) set z = α/2 and z = i −β/2 in (7), respectively, combine according to the Binet form, simplify and make use of (47). To prove (64) set z = α 3 /5 and z = i −β 3 /5 in (7), respectively, combine according to the Binet form, simplify and make use of (48). Identity (65) comes from setting z = α r /L r and z = β r /L r , in turn, in (9) and making use of (49).…”
Section: The Main Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…To prove (63) set z = α/2 and z = i −β/2 in (7), respectively, combine according to the Binet form, simplify and make use of (47). To prove (64) set z = α 3 /5 and z = i −β 3 /5 in (7), respectively, combine according to the Binet form, simplify and make use of (48). Identity (65) comes from setting z = α r /L r and z = β r /L r , in turn, in (9) and making use of (49).…”
Section: The Main Resultsmentioning
confidence: 99%
“…Identity (65) comes from setting z = α r /L r and z = β r /L r , in turn, in (9) and making use of (49). To prove (66) set z = α/ √ 5 and z = −β/ √ 5 in (7), respectively, combine according to the Binet form, simplify and make use of (52). Finally, proceed as before with z = α/2 and z = β/2 in (7), respectively.…”
Section: The Main Resultsmentioning
confidence: 99%