2013
DOI: 10.1016/j.jnnfm.2012.11.007
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Non-incremental transient solution of the Rayleigh–Bénard convection model by using the PGD

Abstract: This paper focuses on the non-incremental solution of transient coupled non-linear models, in particular the one related to the Rayleigh–Bénard flow problem that models natural thermal convection. For this purpose we are applying the so-called Proper Generalized Decomposition that proceeds by performing space-time separated representations of the different unknown fields involved by the flow model. This non-incremental solution strategy allows significant computational time savings and opens new perspectives f… Show more

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Cited by 40 publications
(31 citation statements)
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“…One of them concerns the so-called LBB condition that restricts the free choice of pressure and velocity approximations. As in Aghighi et al (2013) in what follows we consider a penalty formulation of the incompressibility constraint. Thus, the mass balance we are considering writes:…”
Section: Is Enforced At the Bottom Boundarymentioning
confidence: 99%
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“…One of them concerns the so-called LBB condition that restricts the free choice of pressure and velocity approximations. As in Aghighi et al (2013) in what follows we consider a penalty formulation of the incompressibility constraint. Thus, the mass balance we are considering writes:…”
Section: Is Enforced At the Bottom Boundarymentioning
confidence: 99%
“…Functions X u i , X v i and X y i were calculated by solving a series of two-dimensional (2D) boundary value problems and functions Y u i , Y v i and Y y i by solving a series of initial value problems (see Aghighi et al, 2013, for additional details on the solution procedure). Separated representations are involved in the so-called proper generalized decomposition (PGD) methods.…”
Section: Introductionmentioning
confidence: 99%
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“…NACA-4 example. Velocity (quiver fields) and pressure (color maps) solutions of the parametrized NACA-4 airfoils for four representative sets of parameter values{c,t,m,p}:[1]={0.53, 0.13, 0.10, 0.51};[2]={0.55, 0.17, 0.00, 0.50};[3]={0.71, 0.17, 0.07, 0.51};[4]={0.77, 0.23, 0.14, 0.38}.…”
mentioning
confidence: 99%