“…Note that A is a one-dimensional CohenMacaulay domain, e(A) = 2 and m 2 = (x + y)m. Then μ(m n ) = 2 for all n 2 and, by using the algorithm described in [2], it can be checked that m is a normal ideal. On the other hand, in the ring A = CJx, yK/(y 2 ), we have e(A) = 2, m 2 = xm and the ideal K = m 2 = (x 2 , xy) is of type (2), but is not integrally closed as y ∈ K \ K.…”