“…Using the linear system (6.6) for m = 5 and N = 1000 with the initial data V 0 = (0.2373, 0.2273, −0.0124, −0.0023, 0.0001, 0) T , V0 = V0 = (0, 0, 0, 0, 0, 0) T , we compute the approximate solution u 5 (x, t). The efficiency of Algorithm 1 is measured using L 2 , L ∞ and root mean square errors with ∆t = 0.0001, h = 0.01 which are shown in Table 3.The numerical results are compared with the obtained results in [28,23]. It can be concluded that the numerical solutions obtained by our algorithm are good.…”