2016
DOI: 10.1137/140998652
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Numerical Solution of the Poisson Equation on Domains with a Thin Layer of Random Thickness

Abstract: Abstract. The present article is dedicated to the numerical solution of the Poisson equation on domains with a thin layer of different conductivity and of random thickness. By changing the boundary condition, the boundary value problem given on a random domain is transformed into a boundary value problem on a fixed domain. The randomness is then contained in the coefficients of the new boundary condition. This thin coating can be expressed by a random Robin boundary condition which yields a third order accurat… Show more

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Cited by 17 publications
(28 citation statements)
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“…In the k−th step of Newton's method, knowing σ (k−1) , we solve (8) and (11) for u (k−1) , solve (40) for u , and then update σ (k) according to (37). In 1D, we have…”
Section: Resultsmentioning
confidence: 99%
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“…In the k−th step of Newton's method, knowing σ (k−1) , we solve (8) and (11) for u (k−1) , solve (40) for u , and then update σ (k) according to (37). In 1D, we have…”
Section: Resultsmentioning
confidence: 99%
“…When dealing with relatively small input variability and outputs that do not express high nonlinearity, perturbation type methods are most frequently used, where the random solutions are expanded via Taylor series around their mean and truncated at a certain order [21,11]. Typically, at most second-order expansion is used because the resulting system of equations are typically complicated beyond the second order.…”
Section: Introductionmentioning
confidence: 99%
“…[5] already derived the first three terms, u 0 , u 1 and u 2 . But the method we give below seems simpler and does not require the dilation technique and any asymptotic form for the differential operator L used in [5]. Actually, that kind of singular perturbation suits for the case that the solution itself develops a sharp peak in the thin layer, such as the traditional boundary layer analysis in fluid mechanics.…”
Section: The Elliptic Problem With Smooth Coefficientsmentioning
confidence: 99%
“…Note that although u [n] and v [n] have the same approximation order, there might still be a considerable difference in the accuracy of their approximation errors due to the effects of the prefactors. The numerical results in [5] show that the approximation u [n] produces much less accurate results than v [n] for n = 1, 2. This can be easily confirmed by the following simple onedimensional example:…”
Section: 2mentioning
confidence: 99%
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