2016
DOI: 10.1016/j.amc.2016.01.038
|View full text |Cite
|
Sign up to set email alerts
|

Numerical solution of Volterra–Fredholm integral equations via modification of hat functions

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
23
0

Year Published

2017
2017
2023
2023

Publication Types

Select...
7

Relationship

2
5

Authors

Journals

citations
Cited by 36 publications
(23 citation statements)
references
References 19 publications
0
23
0
Order By: Relevance
“…Lemma 3.1 Suppose that H m (v) and Ψ m (v) are respectively given in (10) and 4, H m (v) can be written in accordance with BPFs as follows:…”
Section: Haar Wavelets and Bpfsmentioning
confidence: 99%
See 1 more Smart Citation
“…Lemma 3.1 Suppose that H m (v) and Ψ m (v) are respectively given in (10) and 4, H m (v) can be written in accordance with BPFs as follows:…”
Section: Haar Wavelets and Bpfsmentioning
confidence: 99%
“…As we all know, many stochastic Volterra integral equations do not have exact solutions, so it makes sense to find more precise approximate solutions to stochastic Volterra integral equations. There are different numerical methods to stochastic Volterra integral equations, for example, orthogonal basis methods [1][2][3][4][5][6][7][8][9][10], wash series methods [11,12], and polynomials methods [13][14][15][16].…”
Section: Introductionmentioning
confidence: 99%
“…Example Consider the following nonlinear FPQIDE with given initial conditions leftuxyx+uxyy+2uxyxy+uxy=x12sinxy4+H1.H2,H1=1Γ92Γ1120x0y()xs72()yt92x+costu2stdtdsH2=1Γ72Γ1320x0y()xs52()yt112ysin()s+t8u2stdtds,ux0=0,u0y=0, whose exact solution u ( x , y ) is unknown. Since the exact solution of this example is not known, the maximum absolute error is calculated using the following double mesh principle En=supRnxy,xy…”
Section: Numerical Examplesmentioning
confidence: 99%
“…whose exact solution u(x, y) is unknown. Since the exact solution of this example is not known, the maximum absolute error is calculated using the following double mesh principle [23] E n = sup R n (x, y), (x, y) ∈ ,…”
Section: Proof Letmentioning
confidence: 99%
“…MHFs have the following properties: hifalse(1.5ptjhfalse)={array1arrayi=j,array0arrayij. Let boldHfalse(xfalse)=[]h0false(xfalse),h1false(xfalse),,hnfalse(xfalse)T. According to Equation and expanding entries of H ( x ) H T ( x ) by using MHFs, we have boldHfalse(xfalse)HTfalse(xfalse)=diag()boldHfalse(xfalse). If F be an arbitrary vector of order ( n +1), by using Equation , we have boldHfalse(xfalse)HTfalse(xfalse)F=trueF^boldHfalse(xfalse), where trueF^ is an ( n +1)×( n +1) diagonal matrix with diagonal elements equal to the entries of vector F . Also, if A be a ( n +1)×( n +1) matrix, we have HTfalse(xfalse)AboldHfalse(xfalse)=HTfalse(xfalse)Â=ÂTboldHfalse(xfalse), where  is an ( n +1) vector with elements equal to the diagonal entries of matrix A .…”
Section: Preliminariesmentioning
confidence: 99%