“…We now see from (26) that i.e., F 1 and F 2 are families of G-equivariant maps. Note that, as X and Y are invariant, g(x, y) = (gx, gy) for g ∈ G and (x, y) ∈ X ⊕ Y = H. As the lemma holds in the non-equivariant case, there is a unique family of C 1 -maps η : I × B X → Y that satisfies (27). Now B X is invariant as G acts orthogonally, and thus F 2 (λ, gx, η(λ, gx)) = 0, g ∈ G, x ∈ B X F 2 (λ, gx, gη(λ, x)) = gF 2 (λ, x, η(λ, x)) = 0, g ∈ G, x ∈ B X .…”