2016
DOI: 10.4153/cjm-2015-016-6
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On a Linear Refinement of the Prékopa-Leindler Inequality

Abstract: Abstract. If f , g : R n −→ R ≥0 are non-negative measurable functions, then the Prékopa-Leindler inequality asserts that the integral of the Asplund sum (provided that it is measurable) is greater or equal than the 0-mean of the integrals of f and g. In this paper we prove that under the sole assumption that f and g have a common projection onto a hyperplane, the Prékopa-Leindler inequality admits a linear refinement. Moreover, the same inequality can be obtained when assuming that both projections (not neces… Show more

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Cited by 9 publications
(9 citation statements)
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“…Following the idea of the above proof but now using the linear refinement of the Prékopa-Leindler inequality (see [12,Theorem 1.5]), we immediately get the following improvement of (3.2) for the classical Wills functional.…”
Section: Bounding the Wills Functional Of A Convex Bodymentioning
confidence: 92%
See 1 more Smart Citation
“…Following the idea of the above proof but now using the linear refinement of the Prékopa-Leindler inequality (see [12,Theorem 1.5]), we immediately get the following improvement of (3.2) for the classical Wills functional.…”
Section: Bounding the Wills Functional Of A Convex Bodymentioning
confidence: 92%
“…Proof. Given two log-concave functions f, g : R n −→ R ≥0 (decaying to zero at infinity), if there exists a hyperplane H ∈ G(n, n − 1) such that P H f and P H g have the same (finite) integral, then the right-hand side in the Prékopa-Leindler inequality (2.6) (Theorem B for p = 0) can be replaced by the arithmetic mean of the integrals of f and g (see [12,Theorem 1.5]):…”
Section: Bounding the Wills Functional Of A Convex Bodymentioning
confidence: 99%
“…We notice that a positively decreasing function φ : R −→ R ≥0 is quasi-concave and furthermore φ(0) = sup x∈R φ(x). Thus, as a consequence of [11,Theorem 4.1] we get the following example, which will play a relevant role along this paper.…”
Section: Which Prevents Any Possible Brunn-minkowski Type Inequality ...mentioning
confidence: 92%
“…By the monotonicity and α-concavity of Ω and the inclusion (23), this triple of functions satisfy h (C p,λ,t r γ + D p,λ,t r γ )…”
Section: A Novelmentioning
confidence: 99%
“…To understand the infimal convolution geometrically, we can see that the function u v whose epigraph is the Minkowski sum of the epigraphs of u and v [21][22][23]:…”
Section: Introductionmentioning
confidence: 99%