“…By linearizing(20), we see that[Π(s), s 1 ] + [Π(s 1 ), s] = 0 (23)for all s, s 1 ∈ S. Taking s 1 by s • h in(23), where h ∈ H, we find that[Π(s), sh + hs] + [Π(s) • h + s • Π(h), s] = 0. Putting hby s 1 • s in the above relation, where s 1 ∈ S, we conclude that s[Π(s), s 1 s + ss 1 ] + [Π(s), s 1 s + ss 1 ]s + Π(s)[s 1 s + ss 1 , s] + [s 1 s + ss 1 , s]Π(s) + s[Π(s 1 )s + sΠ(s 1 ) + s 1 Π(s) + Π(s)s 1 , s]…”