“…The fact that these steps yield the set of all solution follows from[11, Theorem 3]. Let C ⊂ Z 8 [D] be the convolutional code with parity-check matrix H(D) =H 0 + H 1 D + H 2 D 2 ∈ Z 8 [D] where H 0 = is easy to check that w(D) = w 0 + w 1 D + w 2 D 2 + w 3 D 3 with w 0 = [5, 5, 0, 6, 0], w 1 = [6,6,4,3,6], w 2 = [2, 1, 1, 2, 0] and w 3 = [2, 6, 4, 0, 0] is a codeword of C. Assume that one receives w…”