2020
DOI: 10.1002/zamm.201900181
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On the three‐dimensional stationary exterior Stokes problem with non standard boundary conditions

Abstract: We study the three‐dimensional stationary exterior Stokes problem with non standard boundary conditions corresponding to a slip‐without‐friction boundary conditions. Because the flow domain is unbounded, we set the problem in weighted spaces in order to control the behavior at infinity of solutions. This functional framework allows to prescribe various behaviors at infinity of the solutions. The established results are related to the existence and the uniqueness of strong and very weak solutions. Our strategy … Show more

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Cited by 7 publications
(7 citation statements)
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“…Proof. The proof of the following theorem is similar to [30,Theorem 7]. Observe that, in view of Proposition 3.5, if the pair (u, π) that belongs to W 0,2 −k−1 (Ω)×W −1,2 −k−1 (Ω) is a solution of (S T ), then for any (ϕ, q) ∈ S k+1 (Ω) × W 1,2 k+1 (Ω), adding (3.6) and (3.7), we have…”
Section: Very Weak Solutionmentioning
confidence: 98%
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“…Proof. The proof of the following theorem is similar to [30,Theorem 7]. Observe that, in view of Proposition 3.5, if the pair (u, π) that belongs to W 0,2 −k−1 (Ω)×W −1,2 −k−1 (Ω) is a solution of (S T ), then for any (ϕ, q) ∈ S k+1 (Ω) × W 1,2 k+1 (Ω), adding (3.6) and (3.7), we have…”
Section: Very Weak Solutionmentioning
confidence: 98%
“…The proofs of Lemma 2.3 and Lemma 2.4 can be found in [30]. Finally, in order to write a Green formula, we define for k ∈ Z:…”
Section: -For Anymentioning
confidence: 99%
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“…In the one hand, in the bounded domains, one can refer for instance to [26,8,13,15,16]. In the other hand, the case for the exterior domains, we can just mention [4,25]. The exterior problem (1.1)-(1.2), where as far as know, we can mention [33,29,19].…”
Section: Introductionmentioning
confidence: 99%