“…1 H NMR (500 MHz, methanol-d 4 ) δ 7.49 (s, 1H), 7.00 (d, J = 8.6 Hz, 2H), 6.77 (d, J = 8.6 Hz, 2H), 4.59 (s, 1H), 3.70 (s, 3H). 13 4-Chloro-5-((4-fluorophenyl)amino)-2-methylpyridazin-3(2H)one (8). Following step 1 of the general procedure A (4,5-dichloro-2methylpyridazin-3(2H)-one (532 mg, 2.97 mmol, 1.1 equiv), 4fluoroaniline (300 mg, 2.70 mmol, 1.0 equiv), and N,N-diisopropylethylamine (940 μL, 5.40 mmol, 2.0 equiv)), product 8 was obtained as a white solid (52 mg, 8% yield over two steps).…”