2001
DOI: 10.1016/s1074-9098(01)00247-7
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Peroxides and peroxide-forming compounds

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Cited by 101 publications
(79 citation statements)
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“…28 In fact, when H 2 O 2 was used as the oxidant instead of O 2 , a substantial increase in yields was observed (entries 9–12, Figure 3). When the H 2 O 2 concentration was increased to 15 mM, the observed yield surpassed the 50% threshold (entry 11, 53%).…”
Section: Resultsmentioning
confidence: 97%
“…28 In fact, when H 2 O 2 was used as the oxidant instead of O 2 , a substantial increase in yields was observed (entries 9–12, Figure 3). When the H 2 O 2 concentration was increased to 15 mM, the observed yield surpassed the 50% threshold (entry 11, 53%).…”
Section: Resultsmentioning
confidence: 97%
“…However, THF-containing solvent-pairs shown in Figure 1 may have safety issues when used on a practical scale due to possible formation of peroxides associated with handling THF. 50 The importance of the solvent characteristics has great impact on the greenness of a chemical process. 10,13,21,22 In this work, we consider the following solvent-pairs that consist of the combination of a hydrogen bond donor solvent and a hydrogen bond acceptor solvent as follows: (i) methanol−cyclohexanone (CHN); (ii) methanol−cyclopentanone (CPN); (iii) methanol−ethyl acetate (EtAc); (iv) methanol−γ-valerolactone (GVL); (v) methanol−γ-butyrolactone (GBL); (vi) ethanol−CHN; (vii) ethanol−CPN; (viii) ethanol−GVL; (ix) ethanol−GBL; (x) water−GVL; (xi) water−GBL.…”
Section: ■ Introductionmentioning
confidence: 99%
“…This chemical mechanism is also for alcohol because alcohol is one of peroxide forming compounds [23] X. Discussion X.1.…”
Section: Roch3 + O2 → Roch2ooh (Hydroperoxide) --------------Equationmentioning
confidence: 98%
“…X.6.The formation of peroxide in methyl ether and methanol is very rear because the peroxides formed from diethyl ether and higher. And from propel alcohol and higher molecular Wight [23]. To explain this phenomenon, we may say that BA in solvent contains electron rich atom with high electronagativty under goes free radical reaction slowly to form benzoic hydro peroxide.Then slowly react with another BA molecule to form BPO.…”
Section: Roch3 + O2 → Roch2ooh (Hydroperoxide) --------------Equationmentioning
confidence: 99%