“…But the excited levels of 9 Be will well-known decay into one neutron and two α particles spontaneously. The residual nucleus of (n, nα), (n, αn), and (n, 5 He) channels is 8 Be, which is unstable and will also separate into two alpha particles spontaneously, as the case of residual nucleus 5 He produced from (n, 2α) channel. Hence the (n, α), (n, nα), (n, αn), (n, 2α), and (n, 5 He) reaction channels will contribute to the (n, n3α) reaction channel, which may proceed via a number of different reaction channels, i.e., as a sequential two-body reaction or two-body breakup process.…”