2016
DOI: 10.1016/j.jalgebra.2016.08.027
|View full text |Cite
|
Sign up to set email alerts
|

Places, cuts and orderings of function fields

Abstract: Abstract. In this paper we investigate the space of R-places of an algebraic function field of one variable. We deal with the problem of determining when two orderings of such a field correspond to a single R-place. To this end we introduce and study the space of cuts on a real curve and prove that the space is homeomorphic to the space of orderings. Finally, we prove that two cuts (consequently, two orderings) correspond to a single R-place if they are induced by a single ultrametric ball.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
4
1

Citation Types

0
15
0

Year Published

2019
2019
2022
2022

Publication Types

Select...
3
1

Relationship

2
2

Authors

Journals

citations
Cited by 4 publications
(15 citation statements)
references
References 8 publications
0
15
0
Order By: Relevance
“…The following result is also proved in [35]: In the paper [26] P. Koprowski and K. Kuhlmann consider the more general case of an algebraic function field F of transcendence degree 1 over a real closed field R.…”
Section: 2mentioning
confidence: 92%
See 1 more Smart Citation
“…The following result is also proved in [35]: In the paper [26] P. Koprowski and K. Kuhlmann consider the more general case of an algebraic function field F of transcendence degree 1 over a real closed field R.…”
Section: 2mentioning
confidence: 92%
“…In this case B determines a cut (always more then one) on the curve. In [26] it is shown that such a cut is a ball cut, and the following theorem is proved:…”
Section: 2mentioning
confidence: 99%
“…In the paper [28] P. Koprowski and K. Kuhlmann consider the more general case of an algebraic function field F of transcendence degree 1 over a real closed field R. Choose any smooth projective model of F , i.e., a smooth, projective algebraic curve over R with function field F . In [26,27] M. Knebusch shows that the curve consists of finitely many semialgebraic connected components, each of which can be endowed with a cyclic order.…”
Section: 2mentioning
confidence: 99%
“…In [26,27] M. Knebusch shows that the curve consists of finitely many semialgebraic connected components, each of which can be endowed with a cyclic order. In [28] this is used to define cuts in these components; the collection of all of them is taken to be the set of cuts on the curve. The following result is proved: By the Baer-Krull Theorem, in the first case there is no other ordering on F that induces the same place as the given one.…”
Section: 2mentioning
confidence: 99%
See 1 more Smart Citation