2009
DOI: 10.1002/jgt.20357
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Polychromatic colorings of bounded degree plane graphs

Abstract: Abstract:A polychromatic k-coloring of a plane graph G is an assignment of k colors to the vertices of G such that every face of G has all k colors on its boundary. For a given plane graph G, one seeks the maximum number k such that G admits a polychromatic k-coloring. In this paper, it is proven that every connected plane graph of order at least three, and maximum degree three, other than K 4 or a subdivision of K 4 on five vertices, admits a 3-coloring in the regular sense (i.e., no monochromatic edges) that… Show more

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Cited by 15 publications
(11 citation statements)
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“…Our main result bounds the minimum possible polychromatic number for plane graphs G with g(G) = g. This settles a question raised in [9]. Note that the set 3g− 5 4 , .…”
Section: Introductionsupporting
confidence: 66%
See 1 more Smart Citation
“…Our main result bounds the minimum possible polychromatic number for plane graphs G with g(G) = g. This settles a question raised in [9]. Note that the set 3g− 5 4 , .…”
Section: Introductionsupporting
confidence: 66%
“…Similarly, a simple consequence of Theorem 2 is the following: Hoffmann and Kriegel [8] proved that the polychromatic number of any plane, bipartite, 2-connected simple graph is at least 3. Horev and Krakovski [9] showed that any connected plane multigraph G with g(G) ≥ 3 and maximum degree at most 3, which is not K 4 , can be colored with 3 colors such that every bounded face of G is polychromatic.…”
Section: Related Workmentioning
confidence: 99%
“…This settles a question raised in [13]. Note that the set { The lower bound for p(G) in (1) remains true when restricting to simple plane graphs G with g(G) = g. Moreover, the constructions for the upper bound in (1) are in fact simple plane graphs.…”
Section: It Is Clear That For Every Plane Graph G P(g(g)) ≤ P(g) ≤ G(g)mentioning
confidence: 74%
“…Horev and Krakovski showed in [13] that any connected plane graph G with g(G) ≥ 3 and maximum degree at most 3, which is not K 4 or a subdivision of K 4 on 5 vertices, are polychromatically 3-colorable. In [7] it is shown that every bipartite cubic plane graph can be colored with 4 colors so that every bounded face of G is polychromatic.…”
Section: Corollary 4 Every Plane Graph G With G(g)mentioning
confidence: 99%
“…Mohar andŠkrekovski [10] proved using the four-color theorem that every simple plane graph admits a polychromatic 2-coloring, later Bose et al [3] proved that without using the four-color theorem. Horev and Krakovski [9] proved that every plane graph of degree at most 3, other than K 4 admits a polychromatic 3-coloring. Horev et al [7] proved that every 2-connected cubic bipartite plane graph admits a polychromatic 4-coloring.…”
Section: Introductionmentioning
confidence: 99%